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3 年
【剑指 Offer】剑指 Offer 34. 二叉树中和为某一值的路径 (C++ dfs bfs ...
找出所有 从根节点到叶子节点 路径总和等于给定目标和的路径。 思路1 dfs,枚举每一条从根节点到叶子节点的路径,当遍历到叶子节点时,如果此时的路径和为目标值,则计入答案。 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode ...
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